Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 14 - Review - Concept Check - Page 1031: 12

Answer

See the explanation below.

Work Step by Step

When $F$ is differentiable, then $\dfrac{\partial z}{\partial x},\dfrac{\partial z}{\partial y}$ can be calculated as: $\dfrac{\partial z}{\partial x}=-\dfrac{\dfrac{\partial F}{\partial x}}{\dfrac{\partial F}{\partial z}}$ and $\dfrac{\partial z}{\partial y}=-\dfrac{\dfrac{\partial F}{\partial y}}{\dfrac{\partial F}{\partial z}}$
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