Answer
$4.5 cm/s^2,9.0 cm/s^2$
Work Step by Step
From the given figure:$\theta= 63.5^\circ$
Thus,
Tangential component of $a$ : $a_T=10 \cos \theta =10 \cos (63.5^\circ)\approx 4.5 cm/s^2$
and
Normal component of $a$ : $a_N=10 \sin \theta =10 \sin (63.5^\circ) \approx 9.0 cm/s^2$
