Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 12 - Section 12.6 - Cylinders and Quadric Surfaces - 12.6 Exercises - Page 882: 35

Answer

Hyperbolic Paraboloid

Work Step by Step

Rewrite as: $2y=2z^{2}-x^{2}$ $\displaystyle \frac{y}{1}=\frac{z^{2}}{1}-\frac{x^{2}}{2}$ On comparing the above form, we find that we have a Hyperbolic Paraboloid $ \dfrac{z}{c}=\dfrac{x^{2}}{a^{2}}-\dfrac{y^{2}}{b^{2}}$ When $z=k$, traces are parabolas opening in the $-y$ direction and when $x=k$, traces are parabolas opening in the $+y$ direction.
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