Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 11 - Section 11.5 - Alternating Series - 11.5 Exercises - Page 773: 24

Answer

The series diverges

Work Step by Step

let $b_{n}$ = $\frac{n^2}{n^2+1}$ Taking the limit of n goes to infinity: $\lim\limits_{n \to \infty}$ $\frac{n^2}{n^2+1}$ = $\lim\limits_{n \to \infty}$ $\frac{1}{1+1/n^2}$ = $\lim\limits_{n \to \infty}$ $\frac{1}{1 + 0 }$ = 1 $\ne$ 0 SO by alternating series test, the original series diverges
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