Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 11 - Section 11.4 - The Comparison Tests - 11.4 Exercises - Page 731: 17

Answer

Converges

Work Step by Step

We know that $\cos n\leq 1$ for all $n\geq 1$. Then, $\frac{1+\cos n}{e^n}\leq\frac{1+1}{e^n}$ so $\frac{1+\cos n}{e^n}\leq \frac{2}{e^n}$ The series $\sum_{n=1}^\infty\frac{2}{e^n}=\sum_{n=1}^\infty 2\cdot (\frac{1}{e})^n$ is an infinite geometric series and it converges because the common ratio is $0<\frac{1}{e}<1$.
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