Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 10 - Section 10.4 - Areas and Lengths in Polar Coordinates - 10.4 Exercises - Page 700: 9

Answer

The area is $4\pi$.

Work Step by Step

Identify the curve: $r=4\cos\theta$ $r^2=4r\cos\theta$ $x^2+y^2=4x$ $x^2+y^2-4x=0$ $(x-2)^2+y^2=4$ It tells us that the polar equation $r=4\cos\theta$ describes a circle centered at $(2,0)$ with the radius of $2$. The area is $A=\pi (radius)^2=\pi\cdot 2^2=4\pi$
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