Answer
FALSE
Work Step by Step
The graph of the parametric equation $x=t^2,y=t^4$ does not have the same graph as $x=t^3,y=t^6$. Why? Because for all $t\in\mathbb{R}$, $x=t^2\geq 0$ and $y=t^4\geq 0$, so that all points on the first graph lie only at quadrant I. Meanwhile, for some negative numbers $t$, $x=t^3< 0$ and $y=t^6< 0$, so that some points on the second graph do not lie only at quadrant I.
Thus, since all points on the first graph are in quadrant I but some points on the other graph are not in quadrant I, the given statement is false.
