Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 64: 19

Answer

$F=\frac{9}{5}C+32$ where $C\geq-273.15$ This is Fahrenheit temperature as a function of Celsius temperature.

Work Step by Step

$C=\frac{5}{9}(F-32)$, where $F\geq-459.67$ $F-32=\frac{9}{5}C$ Inverse function: $F=\frac{9}{5}C+32$ $\because F\geq-459.67, C\geq\frac{5}{9}(-459.67-32)=-273.15$ This is Fahrenheit temperature as a function of Celsius temperature.
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