Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Section 1.2 - Mathematical Models: A Catalog of Essential Functions. - 1.2 Exercises - Page 36: 37

Answer

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Work Step by Step

The surface area of a sphere of radius r is given by $4\pi r^2$. $I=\frac{S}{4\pi r^2}$. If we set $k=\frac{S}{4\pi}$, we can rewrite the above expression as $I=\frac{k}{r^2}$. The initial energy is a positive value, so $k$ is a positive constant. Thus, $I$ satisfies the inverse square law.
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