Answer
a) Jari
b) Jade: $1\text{ mi/h}$
Jari: $\frac{7}{6}\text{ mi/h}$
c) Jade: $f(t)=t+10$
Jari: $f(t)=\frac{7}{6}t$
Work Step by Step
a) The line graph of the driver traveling at the faster speed will have a larger slope. Let us calculate the distance traveled from $t=0$ to $t=6$. Jade's distance changes from 10 to 16 while Jari's distance changes from 0 to 7. Therefore, Jari's speed is larger.
b) Jade: $\frac{16-10}{6-0}=1\text{ mi/h}$
Jari: $\frac{7-0}{6-0}=\frac{7}{6}\text{ mi/h}$
c) Jade: The slope is $1$ and y-intercept is $10$, so $f(t)=t+10$.
Jari: The slope is $\frac{7}{6}$ and y-intercept is $0$, so $f(t)=\frac{7}{6}t$.
