Answer
See proof
Work Step by Step
$\ln e^{rx}=rx \ln e=r(x\ln e)=r\ln e^{x}=\ln (e^{x})^{r}$
Since $\ln$ is a one-to-one function, it follows that
$(e^{x})^{r}=e^{rx}$.
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
APPENDIX G - The Logarithm Defined as an Integral - G Exercises - Page A 60: 7
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