Answer
Area$\approx9.80$
Work Step by Step
The semiperimeter of the triangle
$s=\frac{1}{2}(a+b+c)$
$=\frac{1}{2}(4+5+7)=8$
Area of the triangle
$A=\sqrt {s(s-a)(s-b)(s-c)}$
$=\sqrt {8(8-4)(8-5)(8-7)}=\sqrt {96}\approx 9.80$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
APPENDIX D - Trigonometry - D Exercises - Page A 35: 82
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