Answer
$c\approx3.25$
Work Step by Step
From the law of cosines,
$c^{2}=a^{2}+b^{2}-2ab\cos C$
$= (3.0)^{2}+(4.0)^{2}-2(3.0)(4.0)\cos 53^{\circ}$
$=10.5564394$
$c=\sqrt {10.5564394}\approx3.25$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
APPENDIX D - Trigonometry - D Exercises - Page A 35: 78
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