Answer
$x = \frac{1}{2}(y+3)^2-2$
This is the equation of a parabola with vertex $(-2,-3)$
Work Step by Step
$y^2-2x+6y+5 = 0$
$2x = y^2+6y+5$
$2x = y^2+6y+9-9+5$
$2x = (y+3)^2-4$
$x = \frac{1}{2}(y+3)^2-2$
This is the equation of a parabola with vertex $(-2,-3)$
