Answer
$x \leq -\sqrt{5}~~~~~$ or $~~~~~ x \geq \sqrt{5}$
The solution set is $~~(-\infty,-\sqrt{5}] \cup [\sqrt{5}, \infty)$
Work Step by Step
$x^2 \geq 5$
$\vert x \vert \geq \sqrt{5}$
$x \leq -\sqrt{5}~~~~~$ or $~~~~~ x \geq \sqrt{5}$
The solution set is $~~(-\infty,-\sqrt{5}] \cup [\sqrt{5}, \infty)$
