Answer
$x\leq$(bc-b)/a
Work Step by Step
$(ax+b)/c\leq$b
$ax+b\geq$bc (since $c\lt0$)
$ax\geq$bc-b
$x\leq$(bc-b)/a (since $a\lt0$)
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
APPENDIX A - Numbers, Inequalities, and Absolute Values - A Exercises - Page A10: 60
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
