#### Answer

(4,-1)

#### Work Step by Step

Substitute 0 for x then for y to find two points for each equation. Plot and connect with a line.
$3x+2y=10$
$3(0)+2y=10$
$2y\div2=10\div 2$
$y=5\longrightarrow$ one point is (0,5)
$3x+2y=10$
$3x+2(0)=10$
$3x\div3=10\div3$
$x=3\frac{1}{3}\longrightarrow$ one point is $(3\frac{1}{3},0)$
$2x-3y=11$
$2(0)-3y=11$
$-3y\div-3=11\div-3$
$y=-3\frac{2}{3}\longrightarrow$ one point is $(0,-3\frac{2}{3})$
$2x-3y=11$
$2x-3(0)=11$
$2x\div2=11\div2$
$x=5\frac{1}{2}\longrightarrow$ one point is $(5\frac{1}{2},0)$
The lines intersect at (4,-1).
$3x+2y=3(4)+2(-1)=12-2=10\ \checkmark$
$2x-3y=2(4)-3(-1)=8+3=11\ \checkmark$