Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 9 - Section 9.1 - Solving Pairs of Linear Equations by Graphing - Exercises - Page 327: 11



Work Step by Step

Substitute 0 for x then for y to find two points for each equation. Plot and connect with a line. $3x+2y=10$ $3(0)+2y=10$ $2y\div2=10\div 2$ $y=5\longrightarrow$ one point is (0,5) $3x+2y=10$ $3x+2(0)=10$ $3x\div3=10\div3$ $x=3\frac{1}{3}\longrightarrow$ one point is $(3\frac{1}{3},0)$ $2x-3y=11$ $2(0)-3y=11$ $-3y\div-3=11\div-3$ $y=-3\frac{2}{3}\longrightarrow$ one point is $(0,-3\frac{2}{3})$ $2x-3y=11$ $2x-3(0)=11$ $2x\div2=11\div2$ $x=5\frac{1}{2}\longrightarrow$ one point is $(5\frac{1}{2},0)$ The lines intersect at (4,-1). $3x+2y=3(4)+2(-1)=12-2=10\ \checkmark$ $2x-3y=2(4)-3(-1)=8+3=11\ \checkmark$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.