#### Answer

(2,-1)
(0,-5)
(-2,11)

#### Work Step by Step

First solve for y, then substitute each given value for x to complete the ordered pairs.
$6x+2y=10$
$6x+2y-6x=10-6x\longrightarrow$ subtract 6x from each side
$2y=10-6x$
$2y\div2=(10-6x)\div2\longrightarrow$ divide each side by 2
$y=5-3x$
$y=5-3(2)=5-6=-1$
$y=5-3(0)=5-0-5$
$y=5-3(-2)=5-(-6)=5+6=11$