Answer
$9a^3-5a^2-4a$
Work Step by Step
We divide each term of the polynomial by monomial as follows:
$$
\frac{36a^4 - 20a^3 - 16a^2}{4a}=\frac{36a^4}{4a}-\frac{ 20a^3}{4a}-\frac{ 16a^2}{4a}\\
=9a^3-5a^2-4a
.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 5 - Test - Page 232: 14
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