Elementary Technical Mathematics

$9a^3-5a^2-4a$
We divide each term of the polynomial by monomial as follows: $$\frac{36a^4 - 20a^3 - 16a^2}{4a}=\frac{36a^4}{4a}-\frac{ 20a^3}{4a}-\frac{ 16a^2}{4a}\\ =9a^3-5a^2-4a .$$