Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 5 - Section 5.5 - Multiplication of Polynomials - Exercise - Page 225: 22


$ 4a^3b^3-a^4b^2.$

Work Step by Step

By multiplying each term of the polynomial by the factor $\frac{1}{2}a^2b$, and then adding the products, we have $$ \frac{1}{2}a^2b(8ab^2 - 2a^2b)=\frac{1}{2}a^2b(8ab^2)+ \frac{1}{2}a^2b(- 2a^2b)\\ = 4a^3b^3-a^4b^2. $$
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