Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 5 - Section 5.5 - Multiplication of Polynomials - Exercise - Page 225: 21



Work Step by Step

By multiplying each term of the polynomial by the factor $\frac{2}{3}m$, and then adding the products, we have $$ \frac{2}{3}m(14n - 12m)=\frac{2}{3}m(14n )+\frac{2}{3}m(- 12m)\\ =\frac{28}{3}mn-8m^2=9\frac{1}{3}mn-8m^2. $$
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