# Chapter 5 - Section 5.4 - Multiplication of Monomials - Exercise - Page 223: 12

$-54a^3b^5$

#### Work Step by Step

Multiply the numerical coefficients. Add the powers of the variables. $(-9ab^2)(6a^2 b^3)=(-9\times6)a^{1+2}b^{2+3}=-54a^3b^5$

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