Answer
0.00032, 0.03%
Work Step by Step
For the measurement $15.60~cm$, we have
The precision is $0.01 cm$ (because the last digit $0$ is in the $0.01$ place).
The greatest possible error is one-half the precision:
$0.5\cdot 0.01\ cm=0.00 5 \ cm$
The relative error is
$relative~error=\dfrac{greatest~possible~error}{measurement}$
$\frac{0.005\ cm}{15.60\ cm}=0.00032$
The percent of error is: $0.03\%$
