Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Cumulative Review - Page 209: 5



Work Step by Step

Recall the exponent rules: $x^ax^b=x^{a+b}$ $(x^a)^b=x^{ab}$ $\dfrac{x^a}{x^b}=x^{a-b}$ We simplify as follows: $$ \frac{(10^3\times10^{-2})^3}{10^3\times10^5}=\frac{(10^1)^3}{10^8}=\frac{10^3}{10^8}=\frac{1}{10^5} .$$
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