Answer
$-\dfrac{33}{38}
$
Work Step by Step
Write each mixed number in improper fraction form to obtain:
$=\dfrac{4(2)+3}{4}\div \left(-\dfrac{6(3)+1}{6}\right)
\\=\dfrac{11}{4}\div \left(-\dfrac{19}{6}\right)$
Use the rule $\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}$.
Note that the product and quotient of two numbers with different signs is negative.
$\require{cancel}
=\dfrac{11}{4} \times \left(-\dfrac{6}{19}\right)
\\=\dfrac{11}{\cancel{4}^2} \times \left(-\dfrac{\cancel{6}^3}{19}\right)
\\=\dfrac{11}{2} \times \left(-\dfrac{3}{19}\right)
\\=-\dfrac{11(3)}{2(19)}
\\=-\dfrac{33}{38}
$
