Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 15 - Review - Page 546: 15

Answer

(a) [1,2,3,4,5] (b) $\frac{3}{5}$

Work Step by Step

(a) The sample space would be: [1,2,3,4,5] This is because the spinner is numbered 1-5 and there is only $1$ outcome after each spin. (b) In the sample space found in part (a), we can see that there are $3$ odd numbers out of $5$ possible outcomes. We can then use the formula, $P=\frac{n}{s}$ to calculate the probability of an odd number being spun. $n = 3$ and $s = 5$ $P=\frac{n}{s}$ $P=\frac{3}{5}$
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