Elementary Technical Mathematics

$0.115150$
To multiply the two numbers, the decimals can be initially ignored to obtain $4606 \times 25$. Multiply the numbers to obtain: \begin{array}{ccc} &&\space \text{ }4606 \\&\times &\underline{\space \text{ } \space \text{ }\space \text{ } \space25} \\&&23030 \\&&\underline{\space 9212\space \text{ } \space} \\&&115150\end{array} The first factor has 3 decimals places and the second factor has $3$ decimal places. Thus, the product has $3+3=6$ decimal places. Therefore, the product is $0.115150$.