Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.4 - Formulas - Exercise: 31

Answer

$113.0976\approx113.1$

Work Step by Step

We are given: $P = cd^2SN$, $c=0.7854$, $d=3$, $S=4$, $N=4$: $P=(0.7854)(3)^2*4*4=(0.7854)(9)16=0.7854*144=113.0976\approx113.1$
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