Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.3 - Area and Volume - Exercise - Page 19: 36


2 stores can occupy the space.

Work Step by Step

Find the width of the unleased space. $483-(160+210)=483-370=113 ft$ Find the area of the unleased space. $113\times 90 = 10170 ft^2$ Divide by the minimum space required to determine how many stores could occupy this space. $10170 ft^2 \div \frac{1 store}{4000 ft^2} = 2.5425\ stores$ Round down, since rounding up would mean that the minimum space is not satisfied.
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