## Elementary Technical Mathematics

Dimensions of ceiling are 12ft and 16ft Area of the ceiling = l x b = 12 x 16 = 192 $ft^{2}$ Dimension of left/ right wall are 8ft and 12ft Area of the left/right wall = 2x8x12 = 192 $ft^{2}$ Dimension of front/back wall are 8ft and 16ft Area of the front/back wall = 2x8x16 = 256 $ft^{2}$ Total area = 192 + 192 + 256 = 640 $ft^{2}$ Twenty rooms will be 20 x 640 $ft^{2}$ = 12,800 $ft^{2}$ Area of sheet of drywall is 4ft to 8ft = 32 $ft^{2}$ So, 12,800 ft2÷ 32 ft2 = 400 pieces of dry wall will be needed