Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.16 - Application Involving Percent: Business and Personal Finance - Exercises - Page 96: 19

Answer

$\$10003.92$.

Work Step by Step

Let the money owed $=A$. The given values are Time $t=5\;years$. Borrowed $P=\$8400$. Rate of interest $r=3.5\%=0.035$. Number of periods $n=12$. Formula $A=P(1+\frac{r}{n})^{nt}$. Substitute all values into the formula. $A=8400(1+\frac{0.035}{12})^{12\cdot 5}$. Simplify. $A=8400(1+0.00291666666)^{ 60}$ $A=8400(1.00291666666)^{ 60}$ $A=10003.92$.
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