Answer
The internal diameter is 1.033 in.
Work Step by Step
The internal diameter would be the outside diameter minus the wall thickness twice.
So
$ID = 1.125 in - 0.046 in - 0.046 in $
$ID = 1.033 in$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 1 - Section 1.10 - Addition and Subtraction of Decimal Fractions - Exercises - Page 62: 60
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