Answer
$R=\begin{bmatrix}
6&12\\0&6
\end{bmatrix}$
Work Step by Step
$R=Q^TA$
$R=\begin{bmatrix}
5/6&1/6&-3/6&1/6\\-1/6&5/6&1/6&3/6
\end{bmatrix}\begin{bmatrix}
5&9\\1&7\\-3&-5\\1&5
\end{bmatrix}=\begin{bmatrix}
6&12\\0&6
\end{bmatrix}$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 6 - Orthogonality and Least Squares - 6.4 Exercises - Page 361: 13
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