Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 6 - Orthogonality and Least Squares - 6.1 Exercises - Page 338: 6

Answer

Invertible

Work Step by Step

$det(A)=6 · 4 · 1 + 0 = 24$ The determinant is not 0, so A is invertible.
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