Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 4 - Vector Spaces - 4.1 Exercises - Page 200: 36

Answer

y = [ -4 -8 6 -5] = -0.2[ 3 8 -5 2]+ -0.4[ -5 7 -8 -2]+ 0.6[ -9 -6 3 -9]

Work Step by Step

To do this, we need to check if there exist scalars c1, c2, c3 such that: y = c1a1+c2a2+c3a3 where a1, a2, a3 are columns of A. a1 = [ 3 8 -5 2], a2 = [ -5 7 -8 2], a3 = [ -9 6 -3 -9] Let's represent this system in augmented matrix form and then row reduce to find the solution: [ 3 -5 -9 -4 8 7 -6 -8 -5 -8 3 6 2 -2 -9 -5] rref(aug) = [ 1 0 0 -0.2; 0 1 0 -0.4; 0 0 1 0.6] c1 = -0.2, c2 = -0.4, c3 = 0.6 This system has a solution which confirms that y is in the subspace spanned by the columns of A. Therefore, y = [ -4 -8 6 -5] = -0.2[ 3 8 -5 2]+ -0.4[ -5 7 -8 -2]+ 0.6[ -9 -6 3 -9]
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