Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.1 Exercises - Page 102: 6

Answer

$\begin{bmatrix}0&14\\-3&-9\\13&4\end{bmatrix}$

Work Step by Step

(a) $ \begin{align} AB&=\begin{bmatrix}A\begin{bmatrix}1\\2\end{bmatrix}&A\begin{bmatrix}3\\-1\end{bmatrix}\end{bmatrix}\\ &=\begin{bmatrix}1\begin{bmatrix}4\\-3\\3\end{bmatrix}+2\begin{bmatrix}-2\\0\\5\end{bmatrix}&3\begin{bmatrix}4\\-3\\3\end{bmatrix}-1\begin{bmatrix}-2\\0\\5\end{bmatrix}\end{bmatrix}\\ &=\begin{bmatrix}4-4&12+2\\-3+0&-9+0\\3+10&9-5\end{bmatrix}\\ &=\begin{bmatrix}0&14\\-3&-9\\13&4\end{bmatrix} \end{align} $ (b) $ \begin{align} AB&=\begin{bmatrix}(4)(1)+(-2)(2)&(4)(3)+(-2)(-1)\\(-3)(1)+(0)(2)&(-3)(3)+(0)(-1)\\(3)(1)+(5)(2)&(3)(3)+(5)(-1)\end{bmatrix}\\ &=\begin{bmatrix}4-4&12+2\\-3+0&-9+0\\3+10&9-5\end{bmatrix}\\ &=\begin{bmatrix}0&14\\-3&-9\\13&4\end{bmatrix} \end{align} $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.