Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - Supplementary Exercises - Page 90: 5

Answer

See solution

Work Step by Step

Write augmented matrix for given system and row decreased it: $\left[\begin{array}{ll|l}1 & 3 & k \\ 4 & h & 8\end{array}\right],$ multiply first row with -4 and add to second $\sim\left[\begin{array}{cc|c}1 & 3 & k \\ 0 & h-12 & 8-4 k\end{array}\right]$ Solution is unique if second column is pivot, infinite number of solutions if there is no pivot in second row and no solution if third column is pivot. Unique: $h-12 \neq 0$ $h \neq 12$ Infinite number: $h-12=0$ $h=12$ $8-4 k=0$ $k=2$ No solution: $h-12=0$ $h=12$ $8-4 k \neq 0$ $k \neq 2$ a) Write augmented matrix for given system and row reduce it: $\left[\begin{array}{cc|c}-2 & h & 1 \\ 6 & k & -2\end{array}\right],$ multiply first row with 3 and add to second $\sim\left[\begin{array}{cc|c}-2 & h & 1 \\ 0 & k+3 h & 1\end{array}\right]$ Solution is unique if second column is pivot, infinite number of solutions if there is no pivot in second row and no solution if third column is pivot. Unique: $k+3 h \neq 0$ $k \neq-3 h$ Infinite number: Not possible because element in second row, third column is 1 and No solution: $k+3 h=0$ $k=-3 h$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.