Answer
$u$ and $v$ are linearly independent
Work Step by Step
Because $u$ cannot be written as a scalar multiple of $v$, $u$ and $v$ are linearly independent. Given this, the span of $\{u, v\}$ is $\mathbb{R}$, so any vector $\begin{bmatrix}h\\k\end{bmatrix}$ will be in the span.
