Linear Algebra and Its Applications, 4th Edition

Published by Brooks Cole
ISBN 10: 0030105676
ISBN 13: 978-0-03010-567-8

Chapter 1 - Section 1.2 - The Geometry of Linear Equations - Problem Set - Page 10: 10

Answer

$y_1 + y_3 = 2y_2$

Work Step by Step

For three points to lie on a straight line, they must satisfy the condition that the slope between any two points is the same. Let's denote the points as \( (0, y_1) \), \( (1, y_2) \), and \( (2, y_3) \). The slope between the first two points is: \[ \frac{y_2 - y_1}{1 - 0} = y_2 - y_1 \] The slope between the second and third points is: \[ \frac{y_3 - y_2}{2 - 1} = y_3 - y_2 \] For these three points to lie on a straight line, these slopes must be equal: \[ y_2 - y_1 = y_3 - y_2 \] This can be rearranged to: \[ y_1 + y_3 = 2y_2 \] So, the condition for the points \( (0, y_1) \), \( (1, y_2) \), and \( (2, y_3) \) to lie on a straight line is: \[ y_1 + y_3 = 2y_2 \]
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