## Introductory Algebra for College Students (7th Edition)

Substitute the given distance and solve for t. $d=16t^2$ Substitute the distance for d. $576=16t^2$ Divide both sides by 16. $576 \div 16=16t^2\div16$ Simplify. $36=t^2$ Take the square root of each side. $\sqrt{36}=\sqrt{t^2}$ Simplify. $6=t$