Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Test - Page 621: 3

Answer

$$4\sqrt 3$$

Work Step by Step

We can use the product rule for square roots to rewrite the radicand as the product of a perfect square factor and another factor: $$\sqrt 48 = \sqrt (16 \times 3)$$ Because $16$ is a perfect square factor, we can take the square root of $16$, which is $4$: $$4\sqrt 3$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.