## Introductory Algebra for College Students (7th Edition)

$6^2$; $(\sqrt5)^2$; $36$; $5$; $31$
RECALL: $(a+b)(a-b) =a^2-b^2$ With $a=6$ and $b=\sqrt5$, use the formula above to obtain: $=6^2-(\sqrt5)^2 \\=36-5 \\=31$ Thus, the missing expressions in the given statement are: $6^2$; $(\sqrt5)^2$; $36$; $5$; $31$