Answer
$2x\times\sqrt[3]{3x^2}$
Work Step by Step
$\sqrt[3]{24x^5}$
Factor out the perfect cubes.
$\sqrt[3]{8\times3\times x^3\times x^2}$
Use the product rule for nth roots.
$\sqrt[3]{8}\times\sqrt[3]3\times\sqrt[3]{x^3}\times\sqrt[3]{x^2}$
Simplify.
$2\times\sqrt[3]3\times x\times\sqrt[3]{x^2}$
Use the product rule for nth roots.
$2x\times\sqrt[3]{3x^2}$
