Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.2 - Multiplying and Dividing Radicals - Exercise Set - Page 586: 115



Work Step by Step

$\sqrt[3]{24x^5}$ Factor out the perfect cubes. $\sqrt[3]{8\times3\times x^3\times x^2}$ Use the product rule for nth roots. $\sqrt[3]{8}\times\sqrt[3]3\times\sqrt[3]{x^3}\times\sqrt[3]{x^2}$ Simplify. $2\times\sqrt[3]3\times x\times\sqrt[3]{x^2}$ Use the product rule for nth roots. $2x\times\sqrt[3]{3x^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.