#### Answer

not a real number

#### Work Step by Step

Since the index of the given expression, $
\sqrt{-16}
,$ is even (index = $
2
$) and the radicand is negative (radicand = $
-16
$), then the given expression is $\text{
not a real number
.}$

Published by
Pearson

ISBN 10:
0-13417-805-X

ISBN 13:
978-0-13417-805-9

not a real number

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