Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Cumulative Review Exercises - Page 621: 13


$$x(x + 5)(x - 5)$$

Work Step by Step

For this expression, we see that we can factor out an $x$ for both terms, so we have: $$x(x^2 - 25)$$ The binomial in parentheses is the difference of squares, so we can use the following formula to factor the difference of squares: $$A^2 - B^2 = (A + B)(A - B)$$ In this case, $A$ is the $\sqrt x^2$ or $x$ and $B$ is the $\sqrt 25$ or $5$. Let us plug these values into the formula: $$x(x + 5)(x - 5)$$
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