## Introductory Algebra for College Students (7th Edition)

$20, -12$
With the FOIL method, with m and n being integers, we find that $(x+m)(x+n)=x^{2}+(m+n)x+ mn,$ so ,the sum of m and n is the coefficient of x, and m and n are factors of the constant term. Reversing, when we want to factor $x^{2}+bx+c,$ we search for two integers, m and n such that their sum is b, their product is c. Here, $x^{2}-12x+20,\qquad (b=-12, c=20)$, the product of m and n should be 20, the sum: $-12.$