Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Cumulative Review Exercises - Page 481: 13

Answer

$$2x^4 - x^3 + 3x + 9$$

Work Step by Step

Looking at the numerator of this fraction, we see that we can factor out a $3x$ from all terms. Let us do that first to simplify the fraction a little: $$\frac{3x(2x^4 - x^3 + 3x + 9)}{3x}$$ We see that the $3x$ factor in the numerator and denominator cancel each other out, so we are left with: $$2x^4 - x^3 + 3x + 9$$
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