Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.1 - Adding and Subtracting Polynomials - Exercise Set - Page 349: 97

Answer

$y^{2}-19y+16$

Work Step by Step

Subtract the polynomials inside the first brackets $ \begin{array}{llll} & 4y^{2} & -3y & +8 \\ -( & 5y^{2} & +7y & -4)\\ \hline & & & \\ = & -y^{2} & -10y & +12\\ & & & \end{array} $ Add the polynomials in the second brackets: $ \begin{array}{llll} & 8y^{2} & +5y & -7 \\ +( & -10y^{2} & +4y & +3)\\ \hline & & & \\ = & -2y^{2} & +9y & -4 \end{array} $ Now subtract the results of the brackets: $ \begin{array}{llll} & -y^{2} & -10y & +12 \\ -( & -2y^{2} & +9y & -4)\\ \hline & & & \\ = & y^{2} & -19y & +16 \end{array} $
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