Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Review Exercises - Page 415: 27

Answer

$$12y^{3} + y^{2} - 21y + 10$$

Work Step by Step

To evaluate this expression, we will use the FOIL method to distribute terms. First, we will multiply the first term, $3y$, with each of the terms within the second pair of parentheses. Then we will multiply the second term, $-2$, with each of the terms in the second pair of parentheses: $$12y^{3} + 9y^{2} - 15y - 8y^{2} - 6y + 10$$ Combine like terms: $$12y^{3} + y^{2} - 21y + 10$$
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