Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Mid-Chapter Check Point - Page 378: 7

Answer

$64x^2+48x+9$

Work Step by Step

Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the square of the given expression, $ (8x-3)^2 ,$ is \begin{array}{l}\require{cancel} (8x)^2+2(8x)(3)+(3)^2 \\\\= 64x^2+48x+9 .\end{array}
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